5y^2/y^2-16=10/y-4+6y/y+4

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Solution for 5y^2/y^2-16=10/y-4+6y/y+4 equation: 


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

(5*y^2)/(y^2)-16 = 10/y+(6*y)/y-4+4 // - 10/y+(6*y)/y-4+4

(5*y^2)/(y^2)-(10/y)-((6*y)/y)-16-4+4 = 0

(5*y^2)/(y^2)-10*y^-1-16-6-4+4 = 0

-10*y^-1 = 17 // : -10

y^-1 = -17/10

-1 < 0

1/(y^1) = -17/10 // * y^1

1 = -17/10*y^1 // : -17/10

-10/17 = y^1

y = -10/17

y = -10/17

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